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🧪 Chemistry  ·  Solid State  ·  NEET & JEE

In a close-packed lattice of anions B, cations A occupy two-thirds of the octahedral voids. The formula of the compound is:

Answer: A 2 B 3.

  • A A<sub>2</sub>B<sub>3</sub>
  • B A<sub>3</sub>B<sub>2</sub>
  • C AB<sub>2</sub>
  • D A<sub>2</sub>B

Correct answer: A. A<sub>2</sub>B<sub>3</sub>

Explanation: For N anions there are N octahedral voids; two-thirds filled gives 2N/3 cations, so A:B = 2N/3 : N = 2:3, i.e. A<sub>2</sub>B<sub>3</sub>.

Cubic Unit Cells: Atom PositionsSimple CubicCN=6, 52.4% packedBody-Centred (BCC)CN=8, 68% packedFace-Centred (FCC)CN=12, 74% packed (densest)Corner atoms (shared by 8 cells) shown lighter; body/face-centre atoms shown solid

The three cubic unit cells: Simple Cubic has atoms only at corners; Body-Centred adds one atom at the centre; Face-Centred adds one atom at the centre of each of the 6 faces, giving the highest packing efficiency.

Concept context

Explore the ordered world of crystalline solids: unit cells, packing, defects, and how structure determines electrical and magnetic properties.

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