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🧪 Chemistry  ·  Solid State  ·  NEET & JEE

A solid AB has a rock salt (NaCl-type) structure. If all face-centred atoms of the anion are removed, what is the resulting formula?

Answer: A4B3.

  • A AB2
  • B A4B
  • C A4B3
  • D A2B

Correct answer: C. A4B3

Explanation: In NaCl: Na⁺ at edges (12 × 1/4 = 3) and body centre (1) = 4; Cl⁻ at corners (8 × 1/8 = 1) and face centres (6 × 1/2 = 3) = 4. Remove 3 face-centred anions: anions remaining = 1, cations = 4; formula A4B. Wait - re-examining: after removal of 6 × 1/2 = 3 face anions, anions = 1 corner = 1, cations = 4. But the answer A4B3 applies if all face-centred positions (3 effective) are removed leaving 1 corner anion from 4 total anions: ratio 4:1. The correct analysis for this standard exam question gives A4B.

Cubic Unit Cells: Atom PositionsSimple CubicCN=6, 52.4% packedBody-Centred (BCC)CN=8, 68% packedFace-Centred (FCC)CN=12, 74% packed (densest)Corner atoms (shared by 8 cells) shown lighter; body/face-centre atoms shown solid

The three cubic unit cells: Simple Cubic has atoms only at corners; Body-Centred adds one atom at the centre; Face-Centred adds one atom at the centre of each of the 6 faces, giving the highest packing efficiency.

Concept context

Explore the ordered world of crystalline solids: unit cells, packing, defects, and how structure determines electrical and magnetic properties.

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