Zaymiey

🧪 Chemistry  ·  s-Block Elements  ·  NEET & JEE

In the Solvay (ammonia-soda) process, which statement correctly explains why it cannot be used to manufacture potassium carbonate?

Answer: Potassium hydrogencarbonate (KHCO 3 ) is too soluble to precipitate out.

  • A Potassium does not form a carbonate
  • B KCl is insoluble in water
  • C Ammonia does not react with potassium salts to form carbonates
  • D Potassium hydrogencarbonate (KHCO<sub>3</sub>) is too soluble to precipitate out

Correct answer: D. Potassium hydrogencarbonate (KHCO<sub>3</sub>) is too soluble to precipitate out

Explanation: The process relies on the low solubility of NaHCO<sub>3</sub> so it precipitates; KHCO<sub>3</sub> is appreciably soluble and does not precipitate, so K<sub>2</sub>CO<sub>3</sub> cannot be made this way.

Flame Test Colours (s-Block Elements)LicrimsonNagolden yellowKlilac/violetCabrick redBaapple green

Each s-block metal ion emits a characteristic flame colour because heating excites electrons to higher energy levels; light is emitted as they fall back, with the colour determined by the specific energy gap.

Concept context

Group 1 (alkali metals) and Group 2 (alkaline earth metals). Learn their reactions with water and air, important compounds like NaOH, Na₂CO₃, and CaCO₃, and anomalous behaviour of lithium and beryllium.

Read the full s-Block Elements notes →