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🧪 Chemistry  ·  p-Block Elements (Groups 15 to 18)  ·  NEET & JEE

Xenon forms compounds with fluorine and oxygen because:

Answer: Xe has large atomic radius and low ionisation energy, making it accessible to attack by highly electronegative F.

  • A Xe has large atomic radius and low ionisation energy, making it accessible to attack by highly electronegative F
  • B Xenon possesses readily accessible low-energy d orbitals it can use for bonding as generally observed in typical laboratory settings
  • C Xenon actually behaves chemically as a metal under ordinary laboratory conditions under usual circumstances
  • D Xenon reacts readily with the vast majority of elements on the periodic table according to most researchers

Correct answer: A. Xe has large atomic radius and low ionisation energy, making it accessible to attack by highly electronegative F

Explanation: Xe's low ionisation energy (compared to Kr or Ar) and large polarisable electron cloud allow interaction with strongly electronegative F, and later oxygen-containing agents.

Xenon tetrafluoride XeF4: a central xenon bonded to four fluorine atoms in a square-planar arrangement with two lone pairs above and below, Xe-F bond length 194 pm.

Xenon tetrafluoride (XeF4) has six electron domains around xenon — four Xe–F bonds plus two lone pairs. The lone pairs occupy opposite axial positions, leaving the four fluorine atoms in a square-planar shape (Xe–F ≈ 194 pm). Image: ChemSim, Public Domain, via Wikimedia Commons.

Concept context

Covers the nitrogen family (Group 15), oxygen family (Group 16), halogens (Group 17), and noble gases (Group 18). One of the highest-weightage inorganic chapters in NEET and JEE - includes preparation and properties of HNO₃, H₂SO₄, interhalogens, and xenon compounds.

Read the full p-Block Elements (Groups 15 to 18) notes →