Answer: Electrolysis of brine (NaCl solution) at the anode: 2Cl- → Cl 2 + 2e-.
- A Electrolysis of brine (NaCl solution) at the anode: 2Cl- → Cl<sub>2</sub> + 2e-
- B The thermal decomposition of solid sodium chloride at high temperature
- C The laboratory reaction of concentrated HCl with solid MnO<sub>2</sub>
- D The direct combustion of sodium metal in chlorine gas
Correct answer: A. Electrolysis of brine (NaCl solution) at the anode: 2Cl- → Cl<sub>2</sub> + 2e-
Explanation: The chlor-alkali process electrolyses concentrated NaCl solution; Cl<sub>2</sub> is liberated at the anode, NaOH at the cathode.
Xenon tetrafluoride (XeF4) has six electron domains around xenon — four Xe–F bonds plus two lone pairs. The lone pairs occupy opposite axial positions, leaving the four fluorine atoms in a square-planar shape (Xe–F ≈ 194 pm). Image: ChemSim, Public Domain, via Wikimedia Commons.
Concept context
Covers the nitrogen family (Group 15), oxygen family (Group 16), halogens (Group 17), and noble gases (Group 18). One of the highest-weightage inorganic chapters in NEET and JEE - includes preparation and properties of HNO₃, H₂SO₄, interhalogens, and xenon compounds.