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🧪 Chemistry  ·  p-Block Elements (Groups 15 to 18)  ·  NEET & JEE

Which p-block element exhibits the widest range of allotropes?

Answer: Carbon (diamond, graphite, graphene, fullerene, amorphous carbon, nanotubes...).

  • A Carbon (diamond, graphite, graphene, fullerene, amorphous carbon, nanotubes...)
  • B Sulfur, which forms mainly the rhombic and monoclinic crystal forms in many documented cases
  • C Phosphorus, which forms mainly the white and red allotropic forms according to conventional understanding
  • D Oxygen, which forms mainly the dioxygen and ozone allotropic forms in routine practice

Correct answer: A. Carbon (diamond, graphite, graphene, fullerene, amorphous carbon, nanotubes...)

Explanation: Carbon has the most well-characterised allotropes: diamond, graphite, graphene, fullerenes (C<sub>60</sub>, C<sub>70</sub>...), carbon nanotubes, and amorphous forms.

Xenon tetrafluoride XeF4: a central xenon bonded to four fluorine atoms in a square-planar arrangement with two lone pairs above and below, Xe-F bond length 194 pm.

Xenon tetrafluoride (XeF4) has six electron domains around xenon — four Xe–F bonds plus two lone pairs. The lone pairs occupy opposite axial positions, leaving the four fluorine atoms in a square-planar shape (Xe–F ≈ 194 pm). Image: ChemSim, Public Domain, via Wikimedia Commons.

Concept context

Covers the nitrogen family (Group 15), oxygen family (Group 16), halogens (Group 17), and noble gases (Group 18). One of the highest-weightage inorganic chapters in NEET and JEE - includes preparation and properties of HNO₃, H₂SO₄, interhalogens, and xenon compounds.

Read the full p-Block Elements (Groups 15 to 18) notes →