Answer: NO.
- A NO
- B NO<sub>2</sub>
- C N<sub>2</sub>O
- D N<sub>2</sub>O<sub>5</sub>
Correct answer: A. NO
Explanation: Dilute HNO<sub>3</sub> oxidises copper giving nitric oxide: 3Cu + 8HNO<sub>3</sub> gives 3Cu(NO<sub>3</sub>)<sub>2</sub> + 2NO + 4H<sub>2</sub>O; concentrated acid would give NO<sub>2</sub> instead.
Xenon tetrafluoride (XeF4) has six electron domains around xenon — four Xe–F bonds plus two lone pairs. The lone pairs occupy opposite axial positions, leaving the four fluorine atoms in a square-planar shape (Xe–F ≈ 194 pm). Image: ChemSim, Public Domain, via Wikimedia Commons.
Concept context
Covers the nitrogen family (Group 15), oxygen family (Group 16), halogens (Group 17), and noble gases (Group 18). One of the highest-weightage inorganic chapters in NEET and JEE - includes preparation and properties of HNO₃, H₂SO₄, interhalogens, and xenon compounds.