Answer: H 2 O > H 2 S > H 2 Se > H 2 Te.
- A H<sub>2</sub>Te > H<sub>2</sub>Se > H<sub>2</sub>S > H<sub>2</sub>O
- B H<sub>2</sub>O > H<sub>2</sub>S > H<sub>2</sub>Se > H<sub>2</sub>Te
- C H<sub>2</sub>S > H<sub>2</sub>O > H<sub>2</sub>Se > H<sub>2</sub>Te
- D H<sub>2</sub>O > H<sub>2</sub>Se > H<sub>2</sub>S > H<sub>2</sub>Te
Correct answer: B. H<sub>2</sub>O > H<sub>2</sub>S > H<sub>2</sub>Se > H<sub>2</sub>Te
Explanation: As the central atom gets larger and less electronegative down the group, the bonding pairs move away, so the angle falls: H<sub>2</sub>O (104.5°) > H<sub>2</sub>S > H<sub>2</sub>Se > H<sub>2</sub>Te (~90°).
Xenon tetrafluoride (XeF4) has six electron domains around xenon — four Xe–F bonds plus two lone pairs. The lone pairs occupy opposite axial positions, leaving the four fluorine atoms in a square-planar shape (Xe–F ≈ 194 pm). Image: ChemSim, Public Domain, via Wikimedia Commons.
Concept context
Covers the nitrogen family (Group 15), oxygen family (Group 16), halogens (Group 17), and noble gases (Group 18). One of the highest-weightage inorganic chapters in NEET and JEE - includes preparation and properties of HNO₃, H₂SO₄, interhalogens, and xenon compounds.