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🧪 Chemistry  ·  p-Block Elements (Groups 15 to 18)  ·  NEET & JEE

Nitrogen shows a maximum covalency of 4 whereas phosphorus can extend it to 5 or 6 because:

Answer: nitrogen has no d-orbitals in its valence shell.

  • A nitrogen is more electronegative than phosphorus
  • B nitrogen has a smaller atomic size than phosphorus
  • C nitrogen has no d-orbitals in its valence shell
  • D nitrogen forms stronger pi-bonds than phosphorus

Correct answer: C. nitrogen has no d-orbitals in its valence shell

Explanation: Nitrogen's valence shell (n=2) has no d-orbitals, so it can use only s and p orbitals, limiting covalency to 4; phosphorus has vacant 3d orbitals allowing expansion to 5 or 6.

Xenon tetrafluoride XeF4: a central xenon bonded to four fluorine atoms in a square-planar arrangement with two lone pairs above and below, Xe-F bond length 194 pm.

Xenon tetrafluoride (XeF4) has six electron domains around xenon — four Xe–F bonds plus two lone pairs. The lone pairs occupy opposite axial positions, leaving the four fluorine atoms in a square-planar shape (Xe–F ≈ 194 pm). Image: ChemSim, Public Domain, via Wikimedia Commons.

Concept context

Covers the nitrogen family (Group 15), oxygen family (Group 16), halogens (Group 17), and noble gases (Group 18). One of the highest-weightage inorganic chapters in NEET and JEE - includes preparation and properties of HNO₃, H₂SO₄, interhalogens, and xenon compounds.

Read the full p-Block Elements (Groups 15 to 18) notes →