Answer: N≡N triple bond has very high bond dissociation energy (945 kJ/mol).
- A N≡N triple bond has very high bond dissociation energy (945 kJ/mol)
- B N<sub>2</sub> molecules contain no valence electrons available for bonding
- C Nitrogen atoms have an unusually large atomic radius for their period
- D N<sub>2</sub> is technically classified as a noble gas
Correct answer: A. N≡N triple bond has very high bond dissociation energy (945 kJ/mol)
Explanation: The N≡N triple bond is exceptionally strong (945 kJ/mol), making N<sub>2</sub> difficult to break apart at ordinary temperatures.
Xenon tetrafluoride (XeF4) has six electron domains around xenon — four Xe–F bonds plus two lone pairs. The lone pairs occupy opposite axial positions, leaving the four fluorine atoms in a square-planar shape (Xe–F ≈ 194 pm). Image: ChemSim, Public Domain, via Wikimedia Commons.
Concept context
Covers the nitrogen family (Group 15), oxygen family (Group 16), halogens (Group 17), and noble gases (Group 18). One of the highest-weightage inorganic chapters in NEET and JEE - includes preparation and properties of HNO₃, H₂SO₄, interhalogens, and xenon compounds.