Answer: HNO 3 and HCl (1:3 ratio).
- A HNO<sub>3</sub> and HCl (1:3 ratio)
- B H<sub>2</sub>SO<sub>4</sub> and HNO<sub>3</sub> during normal conditions
- C HCl and H<sub>2</sub>SO<sub>4</sub> as generally observed
- D HNO<sub>3</sub> and H<sub>3</sub>PO<sub>4</sub> in typical laboratory settings
Correct answer: A. HNO<sub>3</sub> and HCl (1:3 ratio)
Explanation: Aqua regia (1 part HNO<sub>3</sub> + 3 parts HCl) dissolves noble metals like gold and platinum.
Xenon tetrafluoride (XeF4) has six electron domains around xenon — four Xe–F bonds plus two lone pairs. The lone pairs occupy opposite axial positions, leaving the four fluorine atoms in a square-planar shape (Xe–F ≈ 194 pm). Image: ChemSim, Public Domain, via Wikimedia Commons.
Concept context
Covers the nitrogen family (Group 15), oxygen family (Group 16), halogens (Group 17), and noble gases (Group 18). One of the highest-weightage inorganic chapters in NEET and JEE - includes preparation and properties of HNO₃, H₂SO₄, interhalogens, and xenon compounds.