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🧪 Chemistry  ·  p-Block Elements (Groups 13 & 14)  ·  NEET & JEE

Fullerene C<sub>60</sub> (Buckminsterfullerene) consists of:

Answer: 20 hexagons and 12 pentagons in a soccer ball arrangement.

  • A 20 hexagons and 12 pentagons in a soccer ball arrangement
  • B Sixty separate hexagonal rings with little pentagons present
  • C Twelve pentagonal rings alone with little hexagons in the structure
  • D A diamond-like cubic lattice of sp<sup>3</sup>-hybridised carbon atoms

Correct answer: A. 20 hexagons and 12 pentagons in a soccer ball arrangement

Explanation: C<sub>60</sub> has exactly 20 hexagonal and 12 pentagonal faces; the pentagonal faces prevent infinite flat-sheet growth, curving it into a sphere.

Carbon Allotropes: Diamond vs GraphiteDiamond (3D network)Every C is sp³, 4 strong bonds→ hardest natural substanceGraphite (layered sheets)weak van der Waals(layers slide → lubricant)Each C is sp², hexagonal sheets→ conducts electricity along sheets

Diamond's rigid 3D tetrahedral network makes it the hardest natural material, while graphite's flat hexagonal sheets are held together only by weak forces, letting them slide past each other (used as a lubricant and in pencils).

Concept context

Covers the Boron family (Group 13: B, Al) and the Carbon family (Group 14: C, Si, Ge, Sn, Pb). Key topics include Lewis acid behaviour of BF₃, borax bead test, silicates, silicones, allotropes of carbon, and trends in properties down the group.

Read the full p-Block Elements (Groups 13 & 14) notes →