Zaymiey

🧪 Chemistry  ·  p-Block Elements (Groups 13 & 14)  ·  NEET & JEE

Diborane is described as electron-deficient. The two bridging B–H–B linkages are best described as:

Answer: Three-centre two-electron (banana) bonds.

  • A Normal two-centre two-electron bonds
  • B Ionic bonds between B<sup>3+</sup> and H<sup>-</sup>
  • C Three-centre two-electron (banana) bonds
  • D Three-centre four-electron bonds

Correct answer: C. Three-centre two-electron (banana) bonds

Explanation: In B<sub>2</sub>H<sub>6</sub> the four terminal B–H bonds are normal 2c-2e bonds, while the two bridges are three-centre two-electron (banana) bonds, explaining its electron deficiency.

Carbon Allotropes: Diamond vs GraphiteDiamond (3D network)Every C is sp³, 4 strong bonds→ hardest natural substanceGraphite (layered sheets)weak van der Waals(layers slide → lubricant)Each C is sp², hexagonal sheets→ conducts electricity along sheets

Diamond's rigid 3D tetrahedral network makes it the hardest natural material, while graphite's flat hexagonal sheets are held together only by weak forces, letting them slide past each other (used as a lubricant and in pencils).

Concept context

Covers the Boron family (Group 13: B, Al) and the Carbon family (Group 14: C, Si, Ge, Sn, Pb). Key topics include Lewis acid behaviour of BF₃, borax bead test, silicates, silicones, allotropes of carbon, and trends in properties down the group.

Read the full p-Block Elements (Groups 13 & 14) notes →