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🧪 Chemistry  ·  Equilibrium  ·  NEET & JEE

The pH of a 0.005 M H<sub>2</sub>SO<sub>4</sub> solution (assume complete dissociation) is:

Answer: 2.

  • A 1
  • B 2
  • C 3
  • D 4

Correct answer: B. 2

Explanation: H<sub>2</sub>SO<sub>4</sub> gives 2H<sup>+</sup>, so [H<sup>+</sup>] = 2 × 0.005 = 0.01 M; pH = −log(0.01) = 2.

ConcentrationTimeReactantsProductsequilibrium reached

As the reaction proceeds, reactant concentration falls and product concentration rises until both level off at equilibrium.

Concept context

When forward and reverse reaction rates are equal, equilibrium is reached. Learn about Kc, Kp, Le Chatelier's principle, and acid-base equilibria, including pH, buffer solutions, and solubility product.

Read the full Equilibrium notes →