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🧪 Chemistry  ·  Electrochemistry  ·  NEET & JEE

For a cell with E = 1.1 V and n = 2, the Gibbs energy change is:

Answer: -212.3 kJ.

  • A -212.3 kJ
  • B +212.3 kJ
  • C -21.23 kJ
  • D -2.12 kJ

Correct answer: A. -212.3 kJ

Explanation: ΔG = -nFE = -2 × 96500 × 1.1 = -212,300 J = -212.3 kJ.

ZnSO4 solutionCuSO4 solutionZnCuAnode (-)Cathode (+)oxidationreductionVSalt bridgee- flow

In a Daniell cell, electrons flow externally from the zinc anode (oxidation) through the voltmeter to the copper cathode (reduction), while the salt bridge completes the circuit.

Concept context

Explore the link between chemical reactions and electricity. Covers galvanic cells, electrolysis, standard electrode potentials, the Nernst equation, and real-world applications like batteries and corrosion.

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