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A current of 0.5 A is passed through molten Al<sub>2</sub>O<sub>3</sub> for 4825 seconds. What mass of aluminium is deposited (Al = 27 g/mol, F = 96500 C)?

Answer: 0.225 g.

  • A 0.675 g
  • B 1.35 g
  • C 0.225 g
  • D 0.45 g

Correct answer: C. 0.225 g

Explanation: Moles of electrons = It/F = (0.5 x 4825)/96500 = 0.025; Al<sup>3+</sup> + 3e- -> Al, so moles of Al = 0.025/3 = 0.00833, mass = 0.00833 x 27 = 0.225 g.

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