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🧪 Chemistry  ·  d- and f-Block Elements  ·  NEET & JEE

The magnetic moment of a complex ion can be used to determine:

Answer: Number of unpaired electrons (and thus high-spin vs low-spin configuration).

  • A Number of unpaired electrons (and thus high-spin vs low-spin configuration)
  • B The exact charge carried by each coordinated ligand
  • C The metal's oxidation state read off directly without any calculation
  • D The precise colour the complex will display in solution

Correct answer: A. Number of unpaired electrons (and thus high-spin vs low-spin configuration)

Explanation: By measuring the magnetic moment and using mu = sqrt(n(n+2)), we can determine n (unpaired electrons), which reveals the spin state and d electron configuration.

Colours of Common Transition Metal Ions (Aqueous)Cu²⁺ blueFe²⁺ pale greenFe³⁺ brown-yellowMn²⁺ pale pinkNi²⁺/Cr³⁺ greenColour arises from d-d electron transitions - d⁰ ions like Sc³⁺, Ti⁴⁺ are colourless

Aqueous solutions of transition metal ions show characteristic colours caused by electrons absorbing visible light to jump between split d-orbitals; the exact colour depends on the metal, its oxidation state, and surrounding ligands.

Concept context

Transition metals (d-block) and lanthanides/actinides (f-block). Known for coloured compounds, variable oxidation states, complex formation, and catalytic properties. Frequently tested in JEE and NEET.

Read the full d- and f-Block Elements notes →