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🧪 Chemistry  ·  d- and f-Block Elements  ·  NEET & JEE

The Bohr magneton (BM) is the unit of magnetic moment. The spin magnetic moment is given by mu = sqrt(n(n+2)). For Fe<sup>3+</sup> (d<sup>5</sup>, high spin), mu =

Answer: 5.92 BM (n=5 unpaired electrons).

  • A 5.92 BM (n=5 unpaired electrons)
  • B 3.87 BM, the value corresponding instead to three unpaired electrons
  • C 1.73 BM, the value corresponding instead to a single unpaired electron
  • D 2.83 BM, the value corresponding instead to two unpaired electrons

Correct answer: A. 5.92 BM (n=5 unpaired electrons)

Explanation: Fe<sup>3+</sup> has d<sup>5</sup> high-spin configuration with 5 unpaired electrons: mu = sqrt(5×7) = sqrt(35) = 5.92 BM.

Colours of Common Transition Metal Ions (Aqueous)Cu²⁺ blueFe²⁺ pale greenFe³⁺ brown-yellowMn²⁺ pale pinkNi²⁺/Cr³⁺ greenColour arises from d-d electron transitions - d⁰ ions like Sc³⁺, Ti⁴⁺ are colourless

Aqueous solutions of transition metal ions show characteristic colours caused by electrons absorbing visible light to jump between split d-orbitals; the exact colour depends on the metal, its oxidation state, and surrounding ligands.

Concept context

Transition metals (d-block) and lanthanides/actinides (f-block). Known for coloured compounds, variable oxidation states, complex formation, and catalytic properties. Frequently tested in JEE and NEET.

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