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🧪 Chemistry  ·  Chemical Kinetics  ·  NEET & JEE

For a reaction with rate = k[A]<sup>2</sup>[B], what happens to the rate if the concentration of both A and B are doubled?

Answer: The rate increases by a factor of 8.

  • A The rate increases by a factor of 2
  • B The rate increases by a factor of 4
  • C The rate increases by a factor of 6
  • D The rate increases by a factor of 8

Correct answer: D. The rate increases by a factor of 8

Explanation: Rate is proportional to [A]<sup>2</sup>[B]; doubling both gives (2)<sup>2</sup> x (2) = 8 times the original rate.

First-Order Decay: Constant Half-Lifetime[A][A]₀[A]₀/22 × t½[A]₀/4Each successive half-life takes the SAME amount of time, regardless of starting concentration

First-order decay curve: concentration halves every t½, and that half-life is constant - a defining test for first-order kinetics.

Concept context

Study the speed of reactions and what affects it: concentration, temperature, and catalysts. Covers rate law, order of reaction, the Arrhenius equation, and reaction mechanisms step by step.

Read the full Chemical Kinetics notes →