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🧪 Chemistry  ·  Amines  ·  NEET & JEE

Why is aniline less basic than methylamine?

Answer: Lone pair is delocalised into benzene ring.

  • A Lone pair is delocalised into benzene ring
  • B Its higher molecular weight reduces the lone pair's basicity
  • C Steric hindrance from the ring blocks proton approach to nitrogen
  • D The aromatic ring raises the electronegativity of the attached nitrogen

Correct answer: A. Lone pair is delocalised into benzene ring

Explanation: In aniline, the N lone pair is delocalised into the aromatic ring, reducing its availability for protonation.

Why Aniline Is a Weaker Base Than MethylamineNCH₃lone pair fully availableMethylamineN donates electrons freely → STRONG baseNlone pair delocalised into ringAniline

In aniline, the nitrogen's lone pair is pulled into the benzene ring through resonance, leaving less electron density available to accept a proton - which is why aniline is a much weaker base than methylamine, where the lone pair is fully available.

Concept context

Nitrogen-containing organic compounds. Covers classification (primary, secondary, tertiary), basicity comparison, preparation methods, and reactions including diazotization and coupling, key for understanding dyes and pharmaceuticals.

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