Answer: 2,4,6-Tribromoaniline.
- A 2,4,6-Tribromoaniline
- B 4-Bromoaniline
- C Bromobenzene
- D Aniline hydrochloride
Correct answer: A. 2,4,6-Tribromoaniline
Explanation: The NH<sub>2</sub> group strongly activates the ring; bromine water produces 2,4,6-tribromoaniline as a white precipitate.
In aniline, the nitrogen's lone pair is pulled into the benzene ring through resonance, leaving less electron density available to accept a proton - which is why aniline is a much weaker base than methylamine, where the lone pair is fully available.
Concept context
Nitrogen-containing organic compounds. Covers classification (primary, secondary, tertiary), basicity comparison, preparation methods, and reactions including diazotization and coupling, key for understanding dyes and pharmaceuticals.