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🧪 Chemistry  ·  Amines  ·  NEET & JEE

What is the product of reaction between aniline and excess methyl iodide followed by AgOH treatment?

Answer: Trimethylphenylammonium hydroxide.

  • A Trimethylphenylammonium hydroxide
  • B N,N-Dimethylaniline left after only partial exhaustive methylation
  • C N-Methylaniline formed after a single methylation step
  • D Phenol formed via hydrolytic displacement of the amino group

Correct answer: A. Trimethylphenylammonium hydroxide

Explanation: Exhaustive methylation gives the quaternary ammonium hydroxide (trimethylphenylammonium hydroxide).

Why Aniline Is a Weaker Base Than MethylamineNCH₃lone pair fully availableMethylamineN donates electrons freely → STRONG baseNlone pair delocalised into ringAniline

In aniline, the nitrogen's lone pair is pulled into the benzene ring through resonance, leaving less electron density available to accept a proton - which is why aniline is a much weaker base than methylamine, where the lone pair is fully available.

Concept context

Nitrogen-containing organic compounds. Covers classification (primary, secondary, tertiary), basicity comparison, preparation methods, and reactions including diazotization and coupling, key for understanding dyes and pharmaceuticals.

Read the full Amines notes →