Answer: N-Methylated amine.
- A N-Methylated amine
- B Amide
- C Nitrile
- D Azo compound
Correct answer: A. N-Methylated amine
Explanation: Leuckart reaction uses HCHO and HCOOH to N-methylate amines via reductive amination.
In aniline, the nitrogen's lone pair is pulled into the benzene ring through resonance, leaving less electron density available to accept a proton - which is why aniline is a much weaker base than methylamine, where the lone pair is fully available.
Concept context
Nitrogen-containing organic compounds. Covers classification (primary, secondary, tertiary), basicity comparison, preparation methods, and reactions including diazotization and coupling, key for understanding dyes and pharmaceuticals.