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🧪 Chemistry  ·  Amines  ·  NEET & JEE

Exhaustive methylation of a tertiary amine followed by AgOH treatment gives a quaternary ammonium hydroxide; heating this causes:

Answer: Hofmann elimination to give alkene.

  • A Hofmann elimination to give alkene
  • B Reduction back to the original tertiary amine
  • C Oxidation of the nitrogen to an N-oxide
  • D A Stevens-type rearrangement of the alkyl groups

Correct answer: A. Hofmann elimination to give alkene

Explanation: Heating quaternary ammonium hydroxide gives Hofmann elimination: alkene + tertiary amine + water.

Why Aniline Is a Weaker Base Than MethylamineNCH₃lone pair fully availableMethylamineN donates electrons freely → STRONG baseNlone pair delocalised into ringAniline

In aniline, the nitrogen's lone pair is pulled into the benzene ring through resonance, leaving less electron density available to accept a proton - which is why aniline is a much weaker base than methylamine, where the lone pair is fully available.

Concept context

Nitrogen-containing organic compounds. Covers classification (primary, secondary, tertiary), basicity comparison, preparation methods, and reactions including diazotization and coupling, key for understanding dyes and pharmaceuticals.

Read the full Amines notes →