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🧪 Chemistry  ·  Aldehydes, Ketones and Carboxylic Acids  ·  NEET & JEE

Which compound liberates CO<sub>2</sub> on treatment with aqueous NaHCO<sub>3</sub>?

Answer: ethanoic acid.

  • A phenol
  • B ethanoic acid
  • C ethanol
  • D propanone

Correct answer: B. ethanoic acid

Explanation: Only carboxylic acids are acidic enough to displace CO<sub>2</sub> from sodium bicarbonate; phenol and alcohols are not.

Nucleophilic Addition to C=ONu:-CORR'CO-RR'Nu

Curved arrows show the nucleophile attacking the carbonyl carbon while the C=O pi electrons move onto oxygen, giving a tetrahedral alkoxide intermediate.

Concept context

Aldehydes, ketones, carboxylic acids, and their derivatives (esters, amides, acid chlorides). Key reactions include nucleophilic addition, Aldol condensation, Cannizzaro, and Claisen. Very heavily tested in JEE and NEET.

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